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35x^2-82x+48=0
a = 35; b = -82; c = +48;
Δ = b2-4ac
Δ = -822-4·35·48
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-82)-2}{2*35}=\frac{80}{70} =1+1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-82)+2}{2*35}=\frac{84}{70} =1+1/5 $
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